Concerning A112237.

[N. J. A. Sloane]

 Yasutoshi,   you said:


    The 3rd case is the following.

         %I A000001
         %S A000001 1,2,3,8,34,
         %N A000001 If a(n-1) is the i-th Fibnacci number then a(n)=Fibonacci(i+a(n-2)); w
ith a(1)=1, a(2)=2, and where we use the following nonstandard indexing for the Fibonacci 
numbers: f(n)=f(n-1)+f(n-2), f(1)=1, f(2)=2 (cf. A000045).
         %e A000001 a(5)=Fibonacci(5+3)=34 because a(4) is 5th Fibonacci number and a(3)=3
 
         %Y A000001 A112237, A000045, A112601.
         %K A000001 nonn
         %O A000001 1,2
         %A A000001 Yasutsohi Kohmoto zbi74583(AT)boat.zero.ad.jp

Me:  this is A005370, no?

Neil