Primes sorted by relation of largest divisors of p+-1

[Hugo Pfoertner]

Thanks to Wouter, Vladeta and Cino.

May I bother you with another similar problem. Not yet submitted, more
manual actions, so higher probability of being wrong:

Primes p such that the number of divisors of p-1 is less than the number
of divisors of p+1.

3 5 11 17 23 29 47 53 59 71 79 83 89 107 131 139 149 167 173 179 191 197
223 227 233 239 251 263 269 293 311 317 347 359 367 383 389 419 431 439
443 449 461 467 479 499 503 509 557 563 569 587 593 599 607 619 643 647
653 659 683 719 727 743 773 797 809

a(1)=3 because d(2)=2 < d(4)=3

Primes p such that the number of divisors of p-1 is greater than the
number of divisors of p+1.

13 31 37 43 61 67 73 97 101 109 113 127 151 157 163 181 193 211 229 241
257 271 277 281 283 313 331 337 353 373 379 397 401 409 421 433 457 463
487 521 523 541 547 571 577 601 613 617 631 641 661 673 677 691 701 709
733 751 757 761 769 787

a(1)=13 because d(12)=6 > d(14)=4.

BTW, equal number of divisors is
http://www.research.att.com/projects/OEIS?Anum=A067889

Hugo