A001176 corrections
David Wilson
davidwwilson at comcast.net
Thu Jan 6 11:22:59 CET 2005
I suggest the following fixes to A001176
%I A001176 M0165 N0064
%S A001176
1,1,2,1,4,2,2,2,2,4,1,2,4,2,2,2,4,2,1,2,2,1,2,2,4,4,2,2,1,2,1,2,2,4,2,
%T A001176
2,4,1,2,2,2,2,2,1,2,2,2,2,2,4,2,2,4,2,2,2,2,1,1,2,4,1,2,2,4,2,2,2,2,2,
%U A001176
1,2,4,4,2,1,2,2,1,2,2,2,2,2,4,2,2,2,4,2,2,2,2,2,2,2,4,2,2,2,1,2,2,2,2
%N A001176 Zeroes in fundamental period of Fibonacci numbers mod n.
The title seems more enlightening than the present title.
Also
{F(n) mod 5} has f.p. (0,1,1,2,3,0,3,3,1,4,0,4,4,3,2,0,2,2,4,1) with 4
zeroes.
{F(n) mod 4} has f.p. (0,1,1,2,3,1), with 1 zero.
{F(n) mod 3} has f.p. (0,1,1,2,0,2,2,1) with 2 zeroes.
{F(n) mod 2} has f.p. (0,1,1) with 1 zero.
{F(n) mod 1} has f.p. (0) with 1 zero.
So logically a(1) = 1, not 0 as given.
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