Gaussian Perfect numbers on Z[i]
y.kohmoto
zbi74583 at boat.zero.ad.jp
Thu Jan 27 08:39:31 CET 2005
[Collection of divisor functions for Gaussian integer ]
Total(n) :
The sum of divisors of n.
Use the first quadrant rule.
No formula exists.
It doesn't have the property of multiplicative.
Sigma(n) :
Product (p_i^( _i+1)-1)/(p_i-1) ....Spira
Where n=Product p_i^ _i
Don't use the first quadrant rule, when you calculate a difference.
GSigma(n) :
Product (Sum(p_i^s_i , 0<=s_i<=r_i)) ....Kohmoto
Where n=Product p_i^ r_i
Use the first quadrant rule, when you calculate a sum.
NSigma(n) :
the sum of the norms of the divisors. ....Franklin T. Adams-Watters
What is the formula?
I would like to define more functions.
UnitarySigma(n) :
Product (p_i^r_i + 1)
Don't use the first quadrant rule, when you calculate a sum
+1UnitarySigma(n) :
Product (p_i^r_i + 1)
Use the first quadrant rule, when you calculate a sum.
+iUnitarySigma(n) :
Product (p_i^r_i + i)
Use the first quadrant rule, when you calculate a sum.
-1UnitarySigma(n) or UnitaryPhi(n) :
Product (p_i^r_i - 1)
Use the first quadrant rule, when you calculate a difference.
-iUnitarySigma(n) or +iUnitaryPhi(n) :
Product (p_i^r_i - i)
Use the first quadrant rule, when you calculate a difference.
NSigma_2(n) :
Product {Sum { Norm(p_i^s_i)^2 , 0<=s_i<=r_i}}
If Norm(m)=Norm(n) then they are counted as one divisor.
It becomes a integer function.
S1 : 1, 3, 6, 18, 18, 42, 38, 93, 84, 126, 102
Name : NSigma_2(n+k*i) . Second line of an array. k=1
S0 : 0, 1, 7, 10, 31, 31, 70, 50, 127, 91, 217
Name : NSigma_2(n+k*i) . The first line of an array. k=0
[Gaussian Perfect numbers]
If m is not 2, then we should add "m-multiple"
Total Gaussian Perfect number :
Total(n)=m*n , for some Gaussian integer m
Example
(1+i)^5*7 m=1+3i
Perfect Gaussian integer : ...McDaniel, Wayne L..
Sigma(n)=m*n , for some Gaussian integer m
Example
(1+i)^5*(2+3i)*3 m=2+i
Gaussian Perfect number :
GSigma(n)=m*n , for some Gaussian integer m
Example
(1+i)^5*7*(2+i)*(1+2i) m=(1+i)^5=4+4i
Unitary Perfect Gaussian integer :
UnitarySigma(n)=m*n , for some Gaussian integer m
Example
(1+i)^5*(2+i)^2 m=1
Unitary Gaussian Perfect number :
+1UnitarySigma(n)=m*n , for some Gaussian integer m
Example
(1+i)^5*(5+4i)*(3+2i)*(2+i)*(1+2i) m=(1+i)^3=2+2i
iUnitary Gaussian Perfect number :
+iUnitarySigma(n)=m*n , for some Gaussian integer m
Example
(1+i)^5*(4+5i)*(2+3i)*(1+2i)*(2+i) m=(1+i)^3=2+2i
-1Unitary Gaussian Perfect number :
-1UnitarySigma(n)=1/m*n , for some Gaussian integer m
Example
(1+i)^5*(2+i)^2*(1+2i) m=1+i
-iUnitary Gaussian Perfect number :
-iUnitarySigma(n)=m*n , for some Gaussian integer m
Example
(1+i)^5*(1+2i)^2* (2+i) m=1+i
I calculated the solutions of the case that (1+i)^5*k , GCD(1+i,k)=1
I will soon post these sequences to OEIS.
Yasutoshi
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