Question about A072087

[Franklin T. Adams-Watters]

Clearly not.  Let f(2) = n > 1, f(3) = n^2, and fill out the rest arbitrarily.  Then the least inverse of n is 2, but the least inverse of n^2 is 3, not 4.

"David Wilson" <davidwwilson at comcast.net> wrote:
>Now I am faced with A072087, which is the least inverse of A072084.  I am 
>tempted to think that the least inverse of any fully multiplicative function 
>is fully multiplicative (where defined), but I'm a little to dizzy to come 
>up with a proof.  Can anyone supply? 

-- 
Franklin T. Adams-Watters
16 W. Michigan Ave.
Palatine, IL 60067
847-776-7645


__________________________________________________________________
Switch to Netscape Internet Service.
As low as $9.95 a month -- Sign up today at http://isp.netscape.com/register

Netscape. Just the Net You Need.

New! Netscape Toolbar for Internet Explorer
Search from anywhere on the Web and block those annoying pop-ups.
Download now at http://channels.netscape.com/ns/search/install.jsp