multiplicatively problematic sequences

[Franklin T. Adams-Watters]

If a function is multiplicative, it's multiplicative, even if only by "accident".  Also, multiplicative is only a property of the values of the function defined on positive integers, so a value at zero makes no difference.

That's my opinion, anyhow.

Mitchell Harris <harris at tcs.inf.tu-dresden.de> wrote:
>In my search for possibly multiplicative sequences, a large number were 
>found that are multiplicative for n >= 1, but somehow it doesn't seem 
>right to call them multiplicative. For example, there are a large number 
>of continued fractions of sqrt(n) that pass the test. See A010121 
>(sqrt(7)), A010122 (sqrt(13)), etc. for examples. It just doesn't seem 
>right somehow that these are multiplicative, yet, as functions, they 
>definitely are. The cyclic nature of these functions helps, as does 
>a(n) = 1 for n odd. 
>
>Is it 'right' that these are multiplicative? They are defined for n=0, but 
>that shouldn't deny their multiplicativity, should it? 
>-- 
>Mitch Harris
-- 
Franklin T. Adams-Watters
16 W. Michigan Ave.
Palatine, IL 60067
847-776-7645


__________________________________________________________________
Switch to Netscape Internet Service.
As low as $9.95 a month -- Sign up today at http://isp.netscape.com/register

Netscape. Just the Net You Need.

New! Netscape Toolbar for Internet Explorer
Search from anywhere on the Web and block those annoying pop-ups.
Download now at http://channels.netscape.com/ns/search/install.jsp