intersection of A48290 and A63986
Max
relf at unn.ac.ru
Fri Jun 24 22:41:46 CEST 2005
Note that
sum(i=1 to x) i-phi(i) = x*(x+1)/2 - sum(i=1 to x) phi(i)
So if x divides sum(i=1 to x) phi(i) and (x+1)/2 is integer (i.e., x is odd), then
x divides sum(i=1 to x) i-phi(i) as well.
Max
Jud McCranie wrote:
> I'm thinking about submitting 1, 5, 25, 249, 617, 13763, 783665, the
> intersection of A48290 and A63986. (I recently extended both of
> these.) A48290 is x such that x divides the sum (i=1 to x) of phi(i).
> A63986 such that x divides the sum (i=1 to x) of i-phi(i). I was
> surprised that about 1/3 of the known terms in A63986 were also in
> A48290. Is there any reason for this?
>
>
>
>
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