better posed problem? (small surprise)

[Meeussen Wouter (bkarnd)]

it is a small surprise that,  for w = Exp[ 2 Pi I /30 ] alias 1^(1/30) ,
w+w^7+w^8+w^18+w^19+w^25  = 0
no cancellation of symmetric pairs, triples or quintuples in sight,
but w+w^7+w^19+w^25 = -w^13  (* four out of five *)
and w^8+w^18 = -w^28 = +w^13  (* two out of three *)

could be called "cancellation by missing parts" ;-))

Wouter Meeussen
Senior Scientist
nv Vandemoortele Izegem
R&D Center
Albertlaan 79, B8870 Izegem
tel +32 (0)51 33 21 24
fax +32 (0)51 33 21 75



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