Hadamard-Matrices

[Annette.Warlich at t-online.de]

Urrks -

 the following is wrong; don't know what output I've misread yesterday...

Am 29.03.05 13:03 schrieb Annette.Warlich at t-online.de:
> 
> One more surprising fact is, that the
> 
>   H4-matrix is just one 6'th root of the 2*I-Matrix.
> 
> That means, not only
> 
>    H4*H4' = I4 ,
> 
> but also
> 
>    H4^6 = I4
> 
It is simply a *fourth* root of 16*I4, so that

   H4^2 = 16*I4

Sorry -

Gottfried Helms