Relation between A011944 and A005246, A002531
Rainer Rosenthal
r.rosenthal at web.de
Sat May 28 01:52:13 CEST 2005
Dear SeqFan,
solving a problem in de.rec.denksport yesterday
(Problem #743 by Gerhard Woeginger) I was urged
to find solutions where 12*t+1 had to be a square
while t itself must be square.
In short: I did have to solve w^2 = (12*h^2 + 1)
in natural numbers w and h. I will write w = w(h)
in the tables below.
Searching the OEIS I did find the h-sequence:
A011944 a(n) = 14a(n-1) - a(n-2) = 0, 2, 28, 390, ...
I will write h(n) in the tables below.
And looking for the w-sequence I did find two
sequences, which are closely related.
A005246 A002531 Equal
1 1 x
1 1 x = w(0) = w(h(0))
1 2
2 5
3
7 7 x = w(2) = w(h(1))
11 19
26 26 x
41 71
97 97 x = w(28) = w(h(2))
153 165
362 362 x
571 989
1351 1351 x = w(390) = w(h(3))
2131 3691
5042 5042 x
7953 13775
18817 18817 x = w(h(4))
29681 51409
70226 70226 x
110771 191861
262087 262087 x = w(h(5))
413403 716035
978122 978122 x
1542841 2672279
3650401 3650401 x = w(h(6))
-------------------------------------------
Table for comparing two sequences.
Legend: w(h) = sqrt(12 h^2 + 1)
h = h(n) = A011944(n)
Once again I have been overwhelmed by the jewellerie
of the OEIS.
What sort of comment would you find appropriate for
my findings? A005246 and A002531 are already connected
by comments.
I would like to make a good comment - but I don't
trust my ability. No fishing for compliments and not
(only) lazyness!
Best regards,
Rainer Rosenthal
r.rosenthal at web.de
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