k-POLYCUBES(n) = n*k-POLYOMINOES(n) ?
magictour at free.fr
magictour at free.fr
Fri May 27 11:08:14 CEST 2005
pauldhanna wrote:
>A048665(n) = n*A093877(n)
>
>URL: http://www.research.att.com/projects/OEIS?Anum=A048665
>Sequence: 1,8,84,936,10810,127632,1531180,18589840,227826873
>Name: Number of rooted 4-dimensional "polycubes" with n cells, with
>no
> symmetries removed.
"rooted" just means, that one cell is specified as root. Divide by n
to get all fixed (don't rotate !) polytesseracts.
>URL: http://www.research.att.com/projects/OEIS?Anum=A093877
>Sequence: 1,4,28,234,2162,21272,218740,2323730,25314097,281299736,
> 3176220308
>Name: Number of fixed n-celled polyzebras (or zebra-move-connected
> polyominoes).
A zebra is a (2,3)leaper, which moves 2 squares in any of the 4 directions
parallel to an axes in 2dim and then (same move) 3 squares ortogonal to that.
I assume that we will get the same counts for (m,n)-leapers with m,n>1 coprime.
Or we get the same counts only for small n ??
I won't expect that polytesseracts and polyzebras counts would
coincide for all n just because 4d has more symmetries than 2d.
But this is just a feeling. Somebody feels differently ?
What's the smallest n, where we could expect different counts ?
-Guenter. sterten(at)aol.com
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