Seqfans, With regard to this discussion, note that the Jacobsthal case : Trading A111075 : F(n) * sum{k|n} 1/F(k), where F(k) is the kth Fibonacci number for J(n) * sum{k|n} 1/J(k), where J(k) is the kth Jacobsthal number (A001045) leads to a set of numbers a(n) that are odd precisely for n=m^2? Paul