sum of first consecutive powers.

[Don Reble]

> %I A113246
> %S A113246 2,3,7,12,16,24
> %N A113246 The smallest number such that
>            1^n +- 2^n +- ... +- a(n)^n = 0 has a solution.

> I verify your results up to a(5) and find a(6) = 31, a(7) = 39.


    Hey, it's not monotonic!

%S A113246 2,3,7,12,16,24,31,39,47,44,60,71,79

    { 3 4 5 6 8 9 10 11 15 19 20 22 23
      24 26 27 29 34 36 37 41 44 45 46 }^8
    sums to half of {1..47}^8, and

    { 3 5 9 10 14 19 20 21 25 26
      28 31 35 36 37 38 40 41 42 }^9
    gives half of {1..44}^9.

-- 
Don Reble  djr at nk.ca

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