NEW A121628

[zak seidov]

PRE-NUMBERED NEW SEQUENCE A121628 FROM Zak Seidov


%I A121628
%S A121628
21,114,333,732,1365,2286,3549,5208,7317,9930,13101,16884,21333,26502,32445,39216,46869,55458,65037,75660,87381,100254,114333,129672,146325,164346,183789,204708,227157,251190,276861,304224,333333,364242,397005,431676,468309,506958,547677,590520
%N A121628 3*n+1 is a perfect cube.
%C A121628 Cf. A001082 3*n+1 is a perfect square.
Intersection of A001082 and A121628 is {21, 1365,
87381,...} 
all of the form (2^(6k)-1)/3.
%F A121628 a(n)=3*n(1+3*n+3*n^2), n=1,2,...,
and corresponding cubes are 3*a(n)+1=(1+3n)^3
%Y A121628 A001082
%O A121628 1
%K A121628 ,nonn,
%A A121628 Zak Seidov (zakseidov at yahoo.com), Aug 12
2006


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