Polynomial sequence?
Nick Hobson
nickh at qbyte.org
Mon Dec 18 00:22:52 CET 2006
Hi,
What do people think of this sequence: 1, 7, 58, 601, 7656, 116929,
2092112, 43006401, 999637120, 25933795801, ... ?
The formula is a(n) = (n+1)^n - n!. Lest that seem completely artificial,
I should comment on how I stumbled across the sequence! Fit a polynomial
f of degree n-1 to the first n nth powers of positive integers. Then
f(n+1) = a(n).
For example, the quadratic that fits (1,1), (2,8), and (3,27) is f(n) =
6n^2-11n+6. Then f(4) = a(3) = 58. Of course, it's not necessary to
actually determine the polynomial f; a(n) can be found by considering
differences.
Nick
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