End of A096779

[Andrew Weimholt]

Actually, it should end much sooner.
A096779(123456788) is the last term, since 0 appears to be excluded
(otherwise 0 should have been the first term).
...And even if we allow 0, it can only be used once according to the 
"not occurring earlier" restriction.

Andrew


-----Original Message-----
From:	zak seidov [SMTP:zakseidov at yahoo.com]
Sent:	Monday, December 18, 2006 11:58 AM
To:	Eric Angelini; seqfan at ext.jussieu.fr
Subject:	Re: End of A096779

A096779(1023456788) is the last term of the sequence
and is the least number consisting of 9's,
9..9, which is not among A096779(1..1023456787).

How many 9's are there in the last term of the
sequence A096779(1023456788),
I don't know (yet?).

Anyway %C'd be added about finiteness of A096779
(with due credit to Eric),
Zak 
 
--- Eric Angelini <Eric.Angelini at kntv.be> wrote:

> 
> Hello SeqFans,
> isn't A096779 a finite sequence?
> http://www.research.att.com/~njas/sequences/A096779
> If I'm not wrong, for n=1023456789 there is no
> possible a(n)...
> 
> A096779 says:
> Smallest number not occurring earlier having in its
> decimal representation no common digit with n.
> 
> 2, 1, 4, 3, 6, 5, 8, 7, 10, 9, 20, 30, 22, 23,
> 24,...
> 
> What could be this last term?
> 
> Best,
> E.
> 
> 


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