Logarithmic numbers

[Paul D. Hanna]

Creighton (and Seqfans),
     Ignoring the leading zeros, the formula is:
 
a(n) = (n+1)*(n+2)/2*sum(k=0,floor(n/2),n!/(n-2*k)! )
 
if so, then your last term is correct.
  
Or, a(n) = A087208(n)*(n+1)*(n+2)/2 , 
where the e.g.f. of  A087208 is exp(x)/(1-x^2).
   
> What could the formula be for this sequence? (warning: the last 
> number given could be wrong)
> 
> 0, 0, 1, 3, 18, 70, 555, 2961, 31108, 213228, 2799765, 23455135,
> 369569046, 3659001138, 67261566463, 768390239085, 16142775951240