S_{0,4}

[Max]

On 2/25/06, koh <zbi74583 at boat.zero.ad.jp> wrote:

>     Have you continued after 3680th term?

Yes. Now I'm at the 4011st iteration factoring 333-bit number.

>     By the way.
>
>     What of the form was the number?
>
>     I suppose that it is of the form p^k-1, becaues Sigma(n)=Product (p_i^(e_i+1)-1)/(p_i-1).
>
>     If so, and p is small, then see site of "Cunningham project".

It was a large composite divisor of the number p+1 where p=P105 was a
prime divisor of 2^373-1.
And, yes, I'm using Cunningham tables to avoid factoring of numbers of
the form 2^k-1.

Currently I'm factoring P103+1 where P103 is a prime divisor of 2^379-1.

Max