Concerning A112237

[koh]

    Neil

    No, it is not A005370 
    The definitions are different.
    So, 6th terms are not same.
    a(6)=Fibonacci(i+a(6-2))=Fibnacci(8+8)=1597, because a(6-1)=8th Fibonacci Number.

    Yasutoshi


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    quote : 


Yasutoshi, you said:


The 3rd case is the following.

%I A000001
%S A000001 1,2,3,8,34,
%N A000001 If a(n-1) is the i-th Fibnacci number then a(n)=Fibonacci(i+a(n-2)); w
ith a(1)=1, a(2)=2, and where we use the following nonstandard indexing for the Fibonacci 
numbers: f(n)=f(n-1)+f(n-2), f(1)=1, f(2)=2 (cf. A000045).
%e A000001 a(5)=Fibonacci(5+3)=34 because a(4) is 5th Fibonacci number and a(3)=3

%Y A000001 A112237, A000045, A112601.
%K A000001 nonn
%O A000001 1,2
%A A000001 Yasutsohi Kohmoto zbi74583(AT)boat.zero.ad.jp

Me: this is A005370, no?

Neil