Sequence A112088 without example

[Graeme McRae]

The similarity of A112088 (the smallest number of people at the start for 
which the last victim is killed in round n+1) to A5428 (the smallest number 
of people at the start for which the last survivor is met in round n) 
suggests the simple formula for A112088:

a(1)=2; a(2)=3; a(n)=floor((5+sum(a(1):a(n-1)))/2)


----- Original Message ----- 
From: "Max" <maxale at gmail.com>
To: "Hugo Pfoertner" <all at abouthugo.de>
Cc: <seqfan at ext.jussieu.fr>
Sent: Friday, June 09, 2006 8:08 PM
Subject: Re: Sequence A112088 without example
> Ops! I've tried to recompute that sequence myself and I've got
> sequence A005428(n+1) which is different from Rainer's one.
>