Sequence A112088 without example
Max
maxale at gmail.com
Sat Jun 10 10:21:57 CEST 2006
On 6/10/06, Hugo Pfoertner <all at abouthugo.de> wrote:
> > Ops! I've tried to recompute that sequence myself and I've got
> > sequence A005428(n+1) which is different from Rainer's one.
[...]
> Using my definition (e.g. "Survivor announces the number of rounds when
> executioner comes to him after having eliminated the final victim) I get
> the following sequence (which is A073941)
It's the same as A005428:
%Y A073941 Apart from initial term, same as A005428, which has further
information.
So, our computations are at least consistent. ;)
Max
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