Formula for A120014(n) -- Simplified

[Gottfried Helms]

Paul -

 thanks for your data. Unfortunately I couldn't proceed
 to success. I couldn't decompose the remaining ST1-like
 matrix; it seems to be something like a difference of
 powers... don't know it yet.
 I'll have not time for this next days, may be even the
 whole week I'm busy and/or on journey. I'll look at things
 again next week (perhaps someone else can find a key in
 the meantime ?)

 Good luck so far -

Gottfried





Am 09.06.2006 15:24 schrieb Paul D Hanna:
> Gottfried,
>        As usual, you have some very nice insights.
> Glad to supply that table (to be submitted as A120013) below (15x15).
> Notice that the first negative term in each row n occurs at about k=n+3
> Thanks for the interest!
>      Paul