A060488: a(n)=n(n+1)(n+11)/6

[Graeme McRae]

It's a good formula if the sequence started at n=1, however that formula is 
no good for this sequence because its offset is 3.  You should use 
a(n)=(n-2)(n-1)(n+9)/6

----- Original Message ----- 
From: "zak seidov" <zakseidov at yahoo.com>
To: <njas at research.att.com>; <seqfan at ext.jussieu.fr>
Sent: Thursday, June 15, 2006 3:29 AM
Subject: A060488: a(n)=n(n+1)(n+11)/6


> Neil, seqfans,
> I added (simple) formula,
> Thanks, Zak
>
> %I A060488
> %S A060488 4,13,28,50,80,119,168,228,300,385,484,598
> %F A060488 a(n)=n(n+1)(n+11)/6
> %A A060488 Zak Seidov, Jun 15 2006
>
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