Diagonal sums of Losanitsch's triangle (A088518?)

[Max A.]

On 6/28/06, Max A. <maxale at gmail.com> wrote:

> In particular, if D(m) denotes the m-th diagonal sum (i.e., the sum
> over n+k=m) of Losanitsch's triangle, then
>
> D(2*m) = A005207(m) = (F(2*m-1) + F(m+1)) / 2
>
> D(2*m+1) = A051450(m) = (F(2*m) + F(m)) / 2
>
> where F() are Fibonacci numbers.

Ops. The latter formula should be:

D(2*m - 1) = A051450(m) = (F(2*m) + F(m)) / 2

Max