Recent sequences lacking keyword "base"

Klaus Brockhaus klaus-brockhaus at t-online.de
Thu Oct 5 20:08:06 CEST 2006


A123179 a(1)=1 a(2)=121, and a(n)=a(n-1) n 2 n 3 n ... n (n-1) n 1, using concatenation.
A123171 a(1) = 123, a(n) = sum of digits of all previous terms.
A123157 Sum of digits of the squares of prime numbers.
A123153 a(n) = nth digit of Pi times the nth prime number. (?)
A123152 Digits of Pi + 1. (?)
A123139 a(n) = prime(n)*(prime(n+1)+1) - (n^3+ sum of digits of n^3).
A123138 The nth digit of a(n-1) gives the position of digit n in a(n), a(1)=263514.
A123137 a(n) = a(n-1)^2 + Sum of the digits of a(n-1), a(1)=1.
A123135 a(n) = n^3 plus sum of digits of n^3.

... and maybe some more. Any objections?

Thanks, Klaus.






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