Sum of decimal digits of 16^n - 1 = 6*n

[zak seidov]

I confirm Max's result; 
additionally, up to 10^4,
the only other case when 
n|sdd(16^n-1)is n=9 with sdd=7n,
Zak 

--- "Max A." <maxale at gmail.com> wrote:

> The sum of decimal digits of 16^n - 1 equals 6*n for
> the following n
> (complete for n up to 10^4):
> 
> 1, 2, 3, 4, 5, 6, 7, 10, 12, 13, 14, 17, 18, 23, 37,
> 43, 46, 60, 119, 183, 223
> 
> Likely, this sequence is finite and there are no
> other terms.
> 
> Does it make sense to add this sequence to OEIS?
> 
> Max
> 
> P.S. Following this discussion in Russian:
> http://community.livejournal.com/ru_math/424139.html
> 



 
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