Sum of decimal digits of 16^n - 1 = 6*n
zak seidov
zakseidov at yahoo.com
Sun Oct 29 21:12:08 CET 2006
No terms up to 10^5,
including cases n|sod(16^n-1)
excluding n=9.
So I suggest to include term 9
and to change definition to smth like:
"Numbers n such that n divides (sum of
digits(16^n-1))"
Zak
--- Van Warren <van at wdv.com> wrote:
> > 1, 2, 3, 4, 5, 6, 7, 10, 12, 13, 14, 17, 18, 23,
> 37, 43, 46, 60, 119,
> > 183, 223
> > Likely, this sequence is finite and there are no
> other terms.
> >
> > Does it make sense to add this sequence to OEIS?
> >
>
> %K A1234567 ,nonn,finite(21),
>
> - Van
>
>
>
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