Fibonacci Collatz 2

[koh]

    Another Fibonacci Collatz sequence.

    See A053521 and A053522

    If we put A=1.5, B=1.5, C=1 then a Fibonacci like and Collatz like sequence is obtained.

    a(n)=(1.5*a(n-2)+1.5*a(n-1)+1)/2^m , 2^m is the highest power of 2 dividing 1.5*a(n-2)+1.5*a(n-1)+1 .

    I calculated it in the cases of several a(1),a(2) pairs.    

    1,1,1,1,1,....
    1,3,7,1,13,11,37,73,83,235,....
    1,5,5,1,5,5,1,5,5,....
    1,7,13,31,67,37,....
    1,9,1,1,1,....
    1,11,19,23,1,37,29,25,41,25,25,19,67,65,199,397,895,....

    They don't exist on OEIS.

    The other way to make the sequence : 
    a(n)=(3*a(n-2)+1+3*a(n-1)+1)/2^m 
        =(1.5*a(n-2)+1.5*a(n-1)+1)/2^m
   
    Yasutoshi