the number of Pluto: 134340: 1,3,4,3,4,0

[zak seidov]

Collatz sequence for Pluto
(not yet in OEIS):

134340,67170,33585,100756,50378,25189,75568,37784,18892,9446,4723,14170,7085,21256,10628,5314,2657,7972,3986,1993,5980,2990,1495,4486,2243,6730,3365,10096,5048,2524,1262,631,1894,947,2842,1421,4264,2132,1066,533,1600,800,400,200,100,50,25,76,38,19,58,29,88,44,22,11,34,17,52,26,13,40,20,10,5,16,8,4,2,1

There are exactly 70 terms ending with 1.

14 terms (1/5 of total 70) are primes:
25189, 4723, 2657, 1993, 2243, 631, 947, 19, 29, 11,
17, 13, 5, 2

Zak


--- cino hilliard <hillcino368 at hotmail.com> wrote:

> 
> 
> 
> >From: zak seidov <zakseidov at yahoo.com>
> >To: Antti Karttunen <antti.karttunen at gmail.com>,
> seqfan at ext.jussieu.fr
> >Subject: Re: the number of Pluto: 134340:
> 1,3,4,3,4,0
> >Date: Thu, 14 Sep 2006 04:53:47 -0700 (PDT)
> >
> >Greetings from The On-Line Encyclopedia
> >of Integer Sequences!
> >
> >Search: 1, 3, 4, 3, 4, 0
> >
> >Displaying 1-1 of 1 results found.
> >
> >A091048  a(n) = the number of steps needed to reach
> >the final value of n via repeated interpretation of
> n
> >as a base b+1 number where b is the largest digit
> of
> >n.
> >  0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 2, 2,
> 3, 4,
> >0, 1, 1, 1, 2, 2, 4, 2, 3, 3, 0, 2, 2, 2, 3,
> >1, 3, 4, 3, 4, 0, (!)
> >2, 2, 2, 3, 3, 1, 2, 1, 4, 0, 3, 3, 3, 4, 2, 4, 3,
> 2,
> >5, 0, 3, 4, 4, 2, 3, 2, 5, 5, 5, 0, 4, 3, 6, 1, 4,
> 5,
> >5, 3, 4, 0, 7, 2, 5, 6, 6, 4, 5, 1, 8, 0, 0, 0, 0,
> 0,
> >0, 0, 0, 0, 0, 0, 1
> 
> 
> 134340 =  2* 2* 3*5*2239
> 
> 2,2,3,5,2239 is not out there.
> 
> Factors of Pluto?
> 
> Hey, we will bring him back and  in a much bigger
> univere than the one he is 
> in now.
> 
> Cino
> 
> 
> 


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