all-base composites
franktaw at netscape.net
franktaw at netscape.net
Tue Sep 12 21:41:00 CEST 2006
First, think of these as polynomials. E.g., 121 is the polynomial
n^2+2n+1.
There are three cases you have to look at:
(1) If the coefficients (digits) all have a common factor, the result
will be
divisible by that factor.
(2) If the polynomial can be factored, the numbers will be composite.
n^2+2n+1 = (n+1)^2, so it is always composite.
(3) Otherwise, you need to look at the polynomial modulo primes up
to its degree. For example, 112 (n^2+n+2, degree 2) modulo 2 is
always 0, so it is always divisible by 2.
Note that condition (1) is really a special case of condition (2),
where one
of the factors is a constant.
If none of the above conditions apply, the polynomial will have prime
values. I don't think this has actually been proved, but it is
certainly true
up to any size you will encounter. You can add a search for a prime
value if you want. Search up to base 1000 or so, and generate some
kind of error message if you don't find a prime.
The continuation after 100 is 110, 112, 114, 116, 118, 120, 121, 130,
132, 134, 136, 138, 140, 143, 144, ....
By the way, this sequence should have the "base" keyword.
Franklin T. Adams-Watters
-----Original Message-----
From: tanyakh at TanyaKhovanova.com
Hello seqfans,
I recently submitted a sequence I really like. I am also suggesting a
name for
it: all-base composites.
I am not sure how to code this sequence. Can you help?
A121719 Strings of digits which are composite regardless of the base
in which
they are interpreted. Exclude bases in which numbers are not
interpretable.
4, 6, 8, 9, 20, 22, 24, 26, 28, 30, 33, 36, 39, 40, 42, 44, 46, 48,
50, 55, 60,
62, 63, 64, 66, 68, 69, 70, 77, 80, 82, 84, 86, 88, 90, 93, 96, 99, 100
EXAMPLE String 55 in every base in which it is interpretable is
divisible by
5. String 1001 in base a is divisible by a+1. Hence 55 and 1001 both
belong to
this sequence.
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