Any updates to A007828?
N. J. A. Sloane
njas at research.att.com
Sat Dec 1 00:05:51 CET 2007
To extend A018216 Maximal number of subgroups in a group with n
elements, is there something better for a(16) than Fisher's group G
with 35 subgroups?
a(17) is of course 2.
There are only 3 nonabelian groups of order 18. Before I count
elements, let me cry plaintively: there must be people here who've
used Sylow's theorems more recently than I have.
This is not, I think, a "hard" sequence, to any real Group Theorist.
In front of you guys, I'm not afraid to show my ignorance, but I'd be
ashamed to drive down to Caltech and ask, say, Michael Aschbacher.
I think C2^4 has 67 subgroups (1 trivial, 15 C2, 35 C2^2, 15 C2^3, 1 itself).
I would suspect that's the largest case, but I'm not in the mood to check all
14 groups of order 16 (and to dig up a description of the more obsure ones.)
------ Original Message ------
<jvospost2 at yahoo.com>
elements
> To extend A018216 Maximal number of subgroups in a group with n
> elements, is there something better for a(16) than Fisher's group G
> with 35 subgroups?
>
> a(17) is of course 2.
>
> There are only 3 nonabelian groups of order 18. Before I count
> elements, let me cry plaintively: there must be people here who've
> used Sylow's theorems more recently than I have.
>
> This is not, I think, a "hard" sequence, to any real Group Theorist.
> In front of you guys, I'm not afraid to show my ignorance, but I'd be
> ashamed to drive down to Caltech and ask, say, Michael Aschbacher.
>
Christian Bower said:
I think C2^4 has 67 subgroups (1 trivial, 15 C2, 35 C2^2, 15 C2^3, 1 itself).
Neil
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