duplicate hunting cont.

Andrew Plewe aplewe at sbcglobal.net
Mon Dec 10 23:17:12 CET 2007


http://www.research.att.com/~njas/sequences/?q=id:A125121|id:A001481&fmt=1
(duplicates as listed, will they ever differ?)

You have right these two are that same because
(4n+1)^3=4(16n^3+12n^2+3n)+1=4k+1 and have partition on sum of two squares

ARTUR


Andrew Plewe pisze:
> Possible duplicates:
> --------------------
>
> http://www.research.att.com/~njas/sequences/?q=id:A071683|id:A001076&fmt=1
> (aside from initial term in A001076)
>
> http://www.research.att.com/~njas/sequences/?q=id:A041299|id:A001112&fmt=1
> (aside from initial zero in A001112)
>
> http://www.research.att.com/~njas/sequences/?q=id:A118579|id:A001297&fmt=1
> (aside from initial zero in A118579)
>
> http://www.research.att.com/~njas/sequences/?q=id:A125121|id:A001481&fmt=1
> (duplicates as listed, will they ever differ?)
>
>
> Misc:
> ------
>
> http://www.research.att.com/~njas/sequences/?q=id:A087327|id:A000982&fmt=1
> (equation for A000982 already noted in comments to A087327, ought to have a
> reference to A000982)
>
> http://www.research.att.com/~njas/sequences/?q=id:A004729|id:A001317&fmt=1
> (A004729 is a subset of A001317)
>
>
> 	-Andrew Plewe-
>
>
>
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