Duplicate hunting cont.

[Andrew Plewe]

What is wrong with

{x=0, y=1}

and/or

{x=0, y=-1}

solutions ?


On Dec 3, 2007 7:34 PM, Max Alekseyev <maxale at gmail.com> wrote:
> On Dec 3, 2007 4:25 PM, Artur <grafix at csl.pl> wrote:
> > P.S.
> > Exactly "Don't existed such integer x,y that
> > 1+2xy+x^2 y+y^2=0 "
>
> Rewrite it as
>
> y*(1+x)^2 = -y^2 + y - 1
>
> Since the l.h.s. of this equality must be divisible by y, we have
> either y=1 or y=-1. But neither of these values corresponds to an
> integer x.
>
> Regards,
> Max
>