Next Problem
Alexander Povolotsky
apovolot at gmail.com
Tue Dec 4 04:34:57 CET 2007
Sorry - you correct.
On Dec 3, 2007 9:46 PM, Alexander Povolotsky <apovolot at gmail.com> wrote:
> What is wrong with
>
> {x=0, y=1}
>
> and/or
>
> {x=0, y=-1}
>
> solutions ?
>
>
> On Dec 3, 2007 7:34 PM, Max Alekseyev <maxale at gmail.com> wrote:
> > On Dec 3, 2007 4:25 PM, Artur <grafix at csl.pl> wrote:
> > > P.S.
> > > Exactly "Don't existed such integer x,y that
> > > 1+2xy+x^2 y+y^2=0 "
> >
> > Rewrite it as
> >
> > y*(1+x)^2 = -y^2 + y - 1
> >
> > Since the l.h.s. of this equality must be divisible by y, we have
> > either y=1 or y=-1. But neither of these values corresponds to an
> > integer x.
> >
> > Regards,
> > Max
> >
>
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