a property of multisets: unit fractions with a twist

[Giovanni Resta]

hv at crypt.org wrote:

> hv at crypt.org wrote:
> :%S A000001 1,1,5,43,875,49506
> 
> Bother, my crude code was cruder than I had realised: both the last two
> terms are wrong. Corrected terms shown in the copy below. I'm not sure
> how I'd go about calculating a(7), I'd welcome thoughts on that.

How did you calculate them ? Maybe if I know your algorithm
I can try to improve/extend it without having to start from scratch

giovanni