A problem

Jonathan Post jvospost3 at gmail.com
Mon Jan 1 21:22:03 CET 2007


If a = b = 1 then f(k) is identically 1.

If a = 1, b arbitrary, then f(3) = (1*b) mod (1+b), and f(4) = (b^2) mod
(1+2b)
That sequence seems at least through the first 10 or 11 terms to be
A123684.  If that's never 0, is it worth rephrasing the definition to a and
b are both integers greater than 1?
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