No automatic replies

[Leroy Quet]

submitting sequences via the on-line form? (I know Tanya has had problems 
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Date: Wed, 4 Jul 2007 12:59:45 -0700
From: "Jonathan Post" <jvospost3 at gmail.com>
To: "Leroy Quet" <qq-quet at mindspring.com>,
   "jonathan post" <jvospost2 at yahoo.com>
Subject: Re: No automatic replies
Cc: seqfan at ext.jussieu.fr
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I got no autoreply for this:

NEW SEQUENCE FROM Jonathan Vos Post

%I A000001
%S A000001 -109, -42, -26, -18, -14, -12, -10, -9, -8,
-7, -6, -6, -5, -5, -5, -4, -4, -4, -4, -4, -3, -3,
-3, -3, -3, -3, -3, -3, -2, -2, -2, -2, -2, -2, -2,
-2, -2, -2, -2, -2, -2, -2, -2, -1
%N A000001 Floor of constants in De Bruijn's approach
to weighted Carleman's inequality.
%C A000001 Abstract of Gao: "We study finite sections
of weighted Carleman's inequality following the
approach of De Bruijn. Similar to the unweighted case,
we obtain an asymptotic expression for the optimal
constant."
%D A000001 N. G. De Bruijn, Carleman's inequality for
finite series, Nederl. Akad. Wetensch. Proc. Ser. A 66
= Indag, pp. 505-514.
%H A000001 Peng Gao, <a
href="http://arxiv.org/PS_cache/arxiv/pdf/0707/0707.0077v1.pdf">Finite
Sections of Weighted Carleman's Inequality</a>, 30
June 2007, p.1.
%F A000001 a(n) = floor(e -
(2*(pi^2)*e)/((log(n))^2)).
%e A000001 a(2) = -109 because e -
(2*(pi^2)*e)/((log(2))^2) ~
-108.9611770171388392925257212314455433803548032218666994709.
a(3) = -42 because e - (2*(pi^2)*e)/((log(3))^2) ~
-41.7382232411477828847325690963577817095329948893743754723.
a(4) = -26 because e - (2*(pi^2)*e)/((log(4))^2) ~
-25.20158288294042589661121470434688897177076548519170518650.
a(30) = -2 because e - (2*(pi^2)*e)/((log(30))^2) ~
-1.92003649778404604739381818236913112747520.
a(45) = -1 because e - (2*(pi^2)*e)/((log(45))^2) ~
-0.98456269963010489451493724472555817336322761419762175593.
%O A000001 2,1
%K A000001 ,easy,sign,
%A A000001 Jonathan Vos Post (jvospost2 at yahoo.com),
Jul 03 2007