SUBMITTING COMMENTS

zak seidov zakseidov at yahoo.com
Sun Jun 3 05:19:59 CEST 2007


Dear Neil, seqfans,

Why not to set up the rule, 
that anyone sending any comments/extensions/editing
etc. SHOULD CC it to all involved ones, 
at least to authors.

[[[As I said many times only Bob does it regularly
(at least he always sends his %C to me)
and I'm always very much grateful to him.]]]

Sometimes VERY INTERESTING moments 
are missing authors
because as I said many times
EDITING is MORE INPORTANT than 
SUBMITTING NEW CONTRIVED SEQUENCES.

All the great editing job done 
mainly by Neil but also by co=editors/commentators 
are simply left unknown to other SFs.

Thanks, Zak


--- "Robert G. Wilson v" <rgwv at rgwv.com> wrote:

> Neil,
> 
>     The offset 1,2 does not agree with the
> %Extensions by Zak Seidov & 
> Lekraj
> Beedassy. I also added an other %Comment line.
> 
> Thanx, Bob.
> 
> 
> %I A038547
> %S A038547 
>
1,3,9,15,81,45,729,105,225,405,59049,315,531441,3645,2025,945,43046721,
> %T A038547 
>
1575,387420489,2835,18225,295245,31381059609,3465,50625,2657205,11025,
> %U A038547 
>
25515,22876792454961,14175,205891132094649,10395,1476225,215233605
> %N A038547 Least number with exactly n odd divisors.
> %C A038547 Also least odd number with exactly n
> divisors. - Lekraj 
> Beedassy (boodhiman(AT)yahoo.com), Aug 30 2006
> %C A038547 If n is prime, a(n)=3^(n-1). - Zak Seidov
> 
> (zakseidov(AT)yahoo.com), Apr 18 2006
> %C A038547 a(2n-1) = {1,9,81,729,225,59049,...} are
> the perfect squares. 
> A122842[n] = Sqrt[ a(2n-1) ] = 
>
{1,3,9,27,15,243,729,45,6561,19683,135,177147,225,105,4782969,14348907,1215,...}.
> 
> - Alexander Adamchuk (alex(AT)kolmogorov.com), Sep
> 13 2006
> %C A038547 Also the least number k such that there
> are n partitions of k 
> whose elements are consecutive integers. i.e.; 1=1,
> 3=1+2=3, 
> 9=2+3+4=4+5=9, 15=1+2+3+4+5=4+5+6=7+8=15, etc. -
> Robert G. Wilson v, 
> (rgwv at rgwv.com), Jun 02 2007
> %H A038547 Don Reble, <a 
>
href="http://www.research.att.com/~njas/sequences/b038547.txt">Table
> of 
> n, a(n) for n = 1..2000</a>
> %H A038547 T. Verhoeff, <a 
>
href="http://www.cs.uwaterloo.ca/journals/JIS/index.html">Rectangular
> 
> and Trapezoidal Arrangements</a>, J. Integer
> Sequences, Vol. 2, 1999, 
> #99.1.6.
> %F A038547 a(n) = A119265(n,n). - Reinhard Zumkeller
> 
> (reinhard.zumkeller(AT)lhsystems.com), May 11 2006
> %F A038547 a(3^(n-1)) = (p(n)#/2)^2 =
> (A002110(n)/2)^2 = A070826(n)^2. 
> For example, a(1) = 1, a(3) = 3^2, a(9) = (3*5)^2,
> a(27) = (3*5*7)^2, 
> a(81) = (3*5*7*11)^2. - Alexander Adamchuk
> (alex(AT)kolmogorov.com), Sep 
> 25 2006
> %Y A038547 Cf. A001227, A005179, A002110, A070826,
> A122842 = Sqrt[ 
> a(2n-1) ].
> %K A038547 nonn,nice
> %O A038547 1,2
> %A A038547 Tom Verhoeff (Tom.Verhoeff(AT)acm.org)
> %E A038547 Corrected by Ron Knott
> (R.Knott(AT)altavista.net), Feb 22, 2001.
> %E A038547 a(30) from Zak Seidov
> (zakseidov(AT)yahoo.com), Apr 18 2006
> %E A038547 a(32)-a(34) from Lekraj Beedassy
> (boodhiman(AT)yahoo.com), 
> Aug 30 2006
>  
> 
> 



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