easy q. about apparent duplicate

[N. J. A. Sloane]

so i will put in a crossreference to that
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Date: Sat, 16 Jun 2007 15:52:41 -0700
From: "Joshua Zucker" <joshua.zucker at gmail.com>
To: njas at research.att.com
Subject: Re: easy q. about apparent duplicate
Cc: seqfan at ext.jussieu.fr
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On 6/16/07, N. J. A. Sloane <njas at research.att.com> wrote:
> Joshua:  many thanks!
>
> So, I will merge the two entries, using your formula,
> %F A087851 a(1) = a(2) = 1; For n > 2, a(n) = |a(n-1)-floor(n*phi)|
>
> In that case, the values that are given now are correct, right?

Wait a second!
The A087851 formula is for A087851, and the values given for that
sequence are correct.

A087852 and A087853 should both be just dead, in my opinion.  There's
no real merging to be done with them since their "recursive"
definitions refer to later terms instead of earlier ones.

> Concerning your more natural-seeming assumption, this seems
> to give Clark Kimberlings sequence,
>
> %S A129229 0,1,2,2,4,4,5,6,6,8,8,9,10,11,11,13,12,15,14,16,16,17,18,19,19,21,21,22,
> %T A129229 23,23,25,25,26,27,28,28,30,29,32,31,33,33,34,35,36,36,38,38,39,40,40,
> %U A129229 42,42,43,44,44,46,46,47,48,49,49,51,50,53,52,54,54,56,55,58,56,60,58
> %N A129229 a(n)=Floor(n*r)-a(n-1), where r is the golden mean, (1+sqrt(5))/2.
>
>
> so i will put in a crossreference to that

Thanks!
--Joshua




when the OEIS reached 100000 sequences we had an e-party: to

I would like to invite those who missed it to join now!

I think it adds greatly to the database to see the other contributors
and where in the whole world they live.

So send me a photo, etc. - see the existing party pages for the style.

I'm sending this also to a few people who are not on the seqfan list.
We are, after all, all friends here.

Neil