Puzzle Sequence

jonscho at hiwaay.net jonscho at hiwaay.net
Tue Jun 26 20:49:34 CEST 2007


Some observations about the terms thus far:

At many (but not all) steps, the hundreds and ones digits are incremented by 1 
and the tens digit is decremented by 1 (yielding a difference of 7*13=91).

If a(n) is in the sequence, then so is a(n)+1001 (unless the latter is 
divisible by 10).  7*11*13=1001.

If any a(n) is divisible by 10, then a(n)/10 is also in the sequence.


Quoting Ralf Stephan <ralf at ark.in-berlin.de>:

> You wrote 
> > Additional elements:
> > 
> > 0 56 147 238 329 560 651 742 798 833 889 924 1001 1057 1148 1239 1470
> 
> > 1561 1652 1743 1799 1834 1925 2002 2058 2149 2380 2471 2562 2653 2744
> 
> Well, the 1st differences so far consist of a sequence containing
> only the numbers 7*5, 7*8, 7*11, 7*13, and 7*33.
> 
> 





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