Pb on A117871

[reismann at free.fr]

Hi seqfans,

So there is a pb on A117871. Neil, Richard, I propose the following correction :
Replace the sequence line :
%S A117871
0,0,4,3,4,5,3,7,4,3,4,11,3,13,4,3,4,17,3,19,4,3,4,23,3,5,4,3,4,29,3,31,
by :
%S A117871 0,4,3,4,5,3,7,4,3,4,11,3,13,4,3,4,17,3,19,4,3,4,23,3,5,4,3,4,29,3,31,

the offset line :
%O A117871 0,3
by :
%O A117871 1,2

and crossrefs line :
%Y A117871 Cf. A090368, A117078, A118534, A117563.
by :
%Y A117871 Cf. A090368, A020639, A117078, A117563, A118534.


The b-files,
b090368.txt (10000) for A090368 :
http://reismann.free.fr/download/b090368.txt
b117871.txt (10000) for A117871 :
http://reismann.free.fr/download/b117871.txt
(0,4,3,4,5,3,7,4,3,4,11,3,13...)

best,

Rémi












Selon Dean Hickerson <dean at math.ucdavis.edu>:

> Russ Cox wrote:
>
> > > There is a little pb on A117871 :
> > > %S A117871
> 0,0,4,3,4,5,3,7,4,3,4,11,3,13,4,3,4,17,3,19,4,3,4,23,3,5,4,3...
> > > Def :
> > > %N A117871 Smallest divisor of 2n that is > 2, or 0 if no such divisor
> exists.
> ...
> > The sequence is correct as it is.
> > The offset line in the sequence indicates
> > that the first term listed is a(0), not a(1).
>
> But a(0) should be 3, not 0.  Every integer is a divisor of 0, and the
> smallest one that's > 2 is 3.
>
> Dean Hickerson
> dean at math.ucdavis.edu
>