New seq submitted, as test: Diagonal of Polygorial array

[Jonathan Post]

Please excuse another email to seqfans so quickly, while I help test
OEIS given njas' warning that it has been mishandling and losing
submissions.  This submission did quickly produce an autoreply email.

NEW SEQUENCE FROM Jonathan Vos Post

%I A000001
%S A000001 18, 576, 6720, 7484400, 2137544640, 981562982400,
 678245967907200, 670873729125600000, 913601739437346960000
%N A000001 Diagonal of Polygorial array A[n,n] = n-th Polygorial for k
 = n, for n>2.
%C A000001 Array A[k,n] = k-th Polygorial(n,k) begins:
k..|..Polygorial(n,k)
3..|.1.1..3..18...180....2700.....56700.....1587600......57153600...
4..|.1.1..4..36...576...14400....518400....25401600....1625702400...
5..|.1.1..5..60..1320...46200...2356200...164934000...15173928000...
6..|.1.1..6..90..2520..113400...7484400...681080400...81729648000...
7..|.1.1..7.126..4284..235620..19085220..2137544640..316356606720...
8..|.1.1..8.168..6720..436800..41932800..5577062400..981562982400...
9..|.1.1..9.216..9936..745200..82717200.12738448800.2598643555200...
10.|.1.1.10.270.14040.1193400.150368400.26314470000.6104957040000...
%e A000001 a(3) = 3rd Polygorial number Polygorial(3,3) = A006472(3) =
 product of the first 3 triangular numbers = 1*3*6 = 18.
a(4) = 4th Polygorial number Polygorial(4,4) = A001044(4) = product of
 the first 4 squares = 1*4*9*16 = 576.
a(5) = 5th Pentagorial number Polygorial(5,5) = A084939(5) = product of
 the first 5 pentagonal numbers = 1 * 5 * 12 * 22 * 35 = 46200.
%Y A000001 Cf. A006472, A001044, A000680, A084939, A084940, A084941,
 A084942, A084943, A084944, A085356.
%O A000001 3,1
%K A000001 ,easy,more,nonn,
%A A000001 Jonathan Vos Post (jvospost2 at yahoo.com), Nov 25 2007
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