A000522 vs A131178 ?
Max Alekseyev
maxale at gmail.com
Tue Oct 30 00:39:48 CET 2007
Yes, these two sequences coincide, expect for the first terms.
Regards,
Max
On 10/29/07, Alexander Povolotsky <apovolot at gmail.com> wrote:
> A000522 Total number of arrangements of a set with n elements:
> a(n) = Sum_{k=0..n} n!/k!.
>
> 1, 2, 5, 16, 65, 326, 1957, 13700, 109601, 986410, 9864101,
> 108505112, 1302061345, 16926797486, 236975164805, 3554627472076,
> 56874039553217, 966858672404690, 17403456103284421,
> 330665665962404000, 6613313319248080001
>
> AUTHOR njas
>
> A131178 Floor( e n! ).
> 2, 2, 5, 16, 65, 326, 1957, 13700, 109601, 986410, 9864101,
> 108505112, 1302061345, 16926797486, 236975164805, 3554627472076,
> 56874039553217, 966858672404690, 17403456103284421,
> 330665665962404000, 6613313319248080001, 138879579704209680022
>
> AUTHOR njas
>
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