Longest Lucas seq. from start to "n"

[Eric Angelini]

Waow, so quick! Thanks to both of you!
There should be a seq in the OEIS, where
a(n) would be the length of the seq. ge-
nerated by "n" (i.e "11" for a(20007))
Best,
É.

>M.H.
>
>gp > find(2007)
>%31 = [11, [2007, 1240, 767, 473, 294, 179, 115, 64, 51, 13, 38]]
>
>gp > round(2007*(sqrt(5)/2-.5))
>%32 = 1240