conjecture: if p is prime, the no. of rings of order p^2 is 11
Neil Fernandez
primeness at borve.org
Sat Apr 12 12:15:24 CEST 2008
In message <L4O$ELA$QIAIFwYJ at borve.org>, Neil Fernandez
<primeness at borve.org> writes
>Let a(n) be the number of rings of order p^2, where p is the nth prime.
>
>These are the 4th, 9th, 25th, 49th, etc. terms of A027623.
>
>The sequence begins: 11,11,11,11
>
>And continues?
The (p^2)th terms of A037289 (no. of order-n commutative rings)
are: 9, 9, 9,
and the (p^2)th terms of A037291 (no. of order-n rings containing 1),
are: 4, 4, 4 ,4
Neil
--
Neil Fernandez
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