Does any "n" exist, such that ( n! + prime(n) ) yields integral square ?

[Alexander Povolotsky]

I extended calculations to n<= 30,000 and still no result.

On Sun, Aug 10, 2008 at 10:01 AM, Alexander Povolotsky
<apovolot at gmail.com> wrote:
> Hi,
>
> Does any "n" exist, such that ( n! + prime(n) ) yields integral square ?
> I tried up to n=3000 to no avail (but my be my PARI program is faulty ;-) ) .
>
> Thanks,
> Regards,
> Alexander R. Povolotsky
>