[seqfan] Re: Subset of A152824

f.firoozbakht at sci.ui.ac.ir f.firoozbakht at sci.ui.ac.ir
Thu Dec 18 14:19:37 CET 2008


According to the current definition terms of the sequence up to 1000
are:

1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22, 24, 33, 36, 44, 48, 55, 66, 77,
88, 99, 111, 112, 115, 122, 124, 126, 128, 132, 135, 144, 155, 162,  
168, 175,184, 212, 216, 222, 223, 224, 244, 248, 264, 288, 289, 312,  
315, 324,
333, 336, 337, 338, 366, 379, 384, 386, 396, 412, 424, 432, 433, 434, 444,
446, 448, 469, 477, 488, 515, 555, 612, 624, 636, 648, 649, 666, 669, 672,
673, 674, 676, 677, 728, 735, 737, 777, 784, 787, 788, 816, 824, 848, 864,
866, 868, 869, 888, 936, 938, 999.

But if we change the definition as I wrote before the terms up to 8000 are:

223, 289, 337, 379, 433, 469, 477, 649, 673, 2227, 2233, 2263, 2269, 2323,
2437, 2449, 2623, 2629, 2773, 2833, 3223, 3277, 3349, 3433, 3493, 3889, 4249,
4333, 4393, 4429, 4633, 4873, 4933, 4969, 6223, 6229, 6433, 6637, 6679, 6763,
6949, 7267, 7477, 7939.


Farideh


Quoting Joshua Zucker <joshua.zucker at gmail.com>:

> Thanks as always to everyone for the polite, friendly, and helpful
> hints, suggestions, and corrections.
>
> In particular:
>
> On Sun, Dec 14, 2008 at 4:50 AM,  <f.firoozbakht at sci.ui.ac.ir> wrote:
>> I think definition of the sequence A152824 according to the
>> first five terms isn't correct.
>> A better definition: Numbers n such that the remainder of n when dividing
>> by each digits of n is equal to one.
>
> Uh oh!  Should 338 be in the sequence or not?
>
> If it should be in the sequence then I need to do a little revision of
> my program.
>
> I suppose I should ask the original author what the intent was, and
> that's what I'll go do now.
>
> I personally don't find it interesting enough to think that both
> sequences, the one beginning 223 289 337 338 379 386 433 434 446 469
> 477 649 669 673 674 676 677 737 787 788 866 868 869 938 and the one
> beginning 223 289 337 379 433 469 477 649 673, need to be in OEIS, but
> if someone else disagrees I'm happy to submit whichever one the author
> didn't intend.  (Probably it's best to direct such emails to me rather
> than further cluttering the list.)
>
> Thanks,
> --Joshua Zucker
>
>
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>
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>









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