Sums payable by exactly n banknotes.
David Wilson
davidwwilson at comcast.net
Sat Feb 16 19:26:32 CET 2008
Let S(n) be the number of amounts achievable using n bills. You are
interested in a(n) = #S(n). Don't forget a(0) = 1 (the single value 0 is
achievable with 0 coins/bills).
Clearly, if gcd(denominatoins) = g > 1, we can divide all denominations by g
without affecting the counts, so WLOG we can assume gcd(denominations) = 1.
At any rate, my guess is that for sufficient n, S(n) includes a large
maximal middle interval M(n) = [x, y] in which all amounts are achievable,
and head and tail sections H(n) = S(n) intersect [0, x-1] and T(n) = S(n)
intersect [y+1, inf]. I suspect that for sufficient n, |M(n)| = (hi-lo)n +
c, where hi and lo are the high and low denominations, while the translated
sets H(n)-x and T(n)-y become constant, or at least periodic in n. This
suggests that in the general case,
|S(n)| = ((hi-lo)/g) n + p(n)
for sufficient n, where p(n) is a periodic function of n.
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