2 or 3 possibly new sequences from 1998

N. J. A. Sloane njas at research.att.com
Sat Jan 26 00:25:17 CET 2008


someone would like to look into them?
 
 
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Date: Sat, 26 Jan 2008 01:26:57 +0100
From: Rainer Rosenthal <r.rosenthal at web.de>
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Subject: Investigating constant C=0.1688... in A081881 comment
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David W. Cantrell wrote:

>>>
>>>             a(n) = 1 + floor(C*exp(n))                 (1)
>>>
>>>    where
>>>
>>>      C = 0.1688563566671442037316797755009010341...    (2)

> In <http://www.research.att.com/~njas/sequences/A081881>,
> Benoit Cloitre had already said that "a(n) is asymptotic to C*exp(n)
> where C=0.1688...", which I suppose that has been proven. My simple
> numerical investigation seemed to indicate that
>
>               0 < a(n) - C*exp(n) < 1.                   (3)
>
> I don't know if that's always true, but if it is, then of course (1)
> holds for all n.

Based on your formula for A136617 we can do more such simple numerical
investigations in a reasonable amount of time. I did so and I found
that (3) doesn't hold for n = 165. I will demonstrate this now.

The value  D(n) = (a(n)-1)/exp(n)  has to be less than C for (**) to hold:

                   D(n)  <  C    is equivalent to (3)

For n=165 we get D(165) =
0.168856356667144203731679775500901034101503956897649222377225522714175330354...

This can't be distinguished from (2) but assuming the truth of your
A136617-formula we can compute better and better approximations for C, using
the monotonically decreasing sequence C(k) = a(k)/exp(k) whose limit is C.

Approximating C by C(k) with k > 168 leads to violations of (3), since C(169) =
0.168856356667144203731679775500901034101503956897649222377225522714175330329...
                                                                           ^^
which is slightly smaller than D(165). This shows

                  a(165) - C*exp(165) > 1

contradicting (3).

Cheers,
Rainer










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