New Sequence from wrong Comment in A083088
Rainer Rosenthal
r.rosenthal at web.de
Mon Jan 7 02:58:54 CET 2008
David W. Cantrell wrote:
> For your sequence giving the greatest number of consecutive integer
> reciprocals, beginning at 1/n, which may be added without exceeding 1,
> I conjecture that
>
> a(n) = floor( (e - 1)n - (e + 1)/2 + (e + 1/e)/(12(2n - 1)) ) + 1
^^^^^^
******* if I am correct, this "+1" is necessary ----/
*******
******* we need a(2) = 2 because 1/2+1/3 < 1 < 1/2+1/3+1/4
*******
Dear David,
numerical checks up to 3^12 verify your formula!
The very fast computation of b(n) allowed another comparison to that
"near-miss" sequence A083088 and I found:
a(n) - A083088(n-1)
------------------- ---------> 0.111750472724977109594431...
n n -> oo
The constant is not in Plouffe's Inverter. The existence of this limit
astonishes me because of the simple definition
A083088(n) = floor(n*(1+sqrt(2))/((1+sqrt(2))-1)) + 1;
Am I right that this has something to do with Paul D. Hanna's findings?
So finally the wrong comment could be turned into an interesting one,
as there is a deeper relationship between A083088(n) and a(n) than just
the match between the first 24 values.
Rainer Rosenthal
r.rosenthal at web.de
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